(15x^2)=(4x)

Solution for (15x^2)=(4x) equation:

(15x^2)=(4x)

We move all terms to the left:

(15x^2)-((4x))=0

determiningTheFunctionDomain
15x^2-4x=0

a = 15; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·15·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*15}=\frac{0}{30}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*15}=\frac{8}{30}
=4/15
$